With a pulse duration of 6 μs and PRF of 1 kHz, what is the duty cycle?

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Multiple Choice

With a pulse duration of 6 μs and PRF of 1 kHz, what is the duty cycle?

Explanation:
Duty cycle is the fraction of time the transmitter is on during one second. It can be found by multiplying the pulse duration by the pulse repetition frequency (or dividing the pulse duration by the period). Here, pulse duration is 6 μs (6×10^-6 s) and PRF is 1 kHz (1000 pulses per second), so the period is 1/PRF = 0.001 s. Duty cycle = 6×10^-6 / 0.001 = 0.006, which is 0.6%.

Duty cycle is the fraction of time the transmitter is on during one second. It can be found by multiplying the pulse duration by the pulse repetition frequency (or dividing the pulse duration by the period). Here, pulse duration is 6 μs (6×10^-6 s) and PRF is 1 kHz (1000 pulses per second), so the period is 1/PRF = 0.001 s. Duty cycle = 6×10^-6 / 0.001 = 0.006, which is 0.6%.

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