Using an attenuation coefficient of about 0.5 dB/cm/MHz, what is the total attenuation in decibels for 3 cm depth at 2 MHz?

Prepare for the Ultrasound Physics Test. Access flashcards and multiple-choice questions, each with hints and explanations. Get set for your exam day!

Multiple Choice

Using an attenuation coefficient of about 0.5 dB/cm/MHz, what is the total attenuation in decibels for 3 cm depth at 2 MHz?

Explanation:
Attenuation adds up with both depth and frequency. The coefficient 0.5 dB per cm per MHz tells us how much energy is lost per centimeter for each MHz of frequency. To get the total loss, multiply by the path length and by the frequency: 0.5 × 3 × 2 = 3 dB. So the beam loses 3 dB over 3 cm at 2 MHz. This also illustrates why higher frequency or longer travel distance increases attenuation. The other numbers would result from omitting either the depth or the frequency factor.

Attenuation adds up with both depth and frequency. The coefficient 0.5 dB per cm per MHz tells us how much energy is lost per centimeter for each MHz of frequency. To get the total loss, multiply by the path length and by the frequency: 0.5 × 3 × 2 = 3 dB. So the beam loses 3 dB over 3 cm at 2 MHz. This also illustrates why higher frequency or longer travel distance increases attenuation. The other numbers would result from omitting either the depth or the frequency factor.

Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy