Using α ≈ 0.5 dB/(cm·MHz), what is the approximate attenuation in dB for 6 cm depth at 3 MHz?

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Multiple Choice

Using α ≈ 0.5 dB/(cm·MHz), what is the approximate attenuation in dB for 6 cm depth at 3 MHz?

Explanation:
Attenuation accumulates with both depth and frequency. The given α tells us how many dB are lost per centimeter for each MHz of frequency. At 3 MHz, the loss per centimeter is 0.5 × 3 = 1.5 dB/cm. Over 6 cm, the total attenuation is 1.5 dB/cm × 6 cm = 9 dB. So the approximate attenuation is 9 dB.

Attenuation accumulates with both depth and frequency. The given α tells us how many dB are lost per centimeter for each MHz of frequency. At 3 MHz, the loss per centimeter is 0.5 × 3 = 1.5 dB/cm. Over 6 cm, the total attenuation is 1.5 dB/cm × 6 cm = 9 dB. So the approximate attenuation is 9 dB.

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