If the speed of sound in tissue is 1540 m/s and the frequency doubles, what happens to the wavelength?

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Multiple Choice

If the speed of sound in tissue is 1540 m/s and the frequency doubles, what happens to the wavelength?

Explanation:
The speed, frequency, and wavelength of a wave are linked by v = f λ. In tissue, the speed of sound is about 1540 m/s and stays essentially constant for ultrasound. If the frequency doubles, the product f λ must stay equal to v. So the new wavelength is λ' = v / (2f) = (1/2)(v / f) = λ/2. In other words, doubling the frequency halves the wavelength. For a quick example, at 1 MHz the wavelength is 1540 / 1,000,000 = 1.54 mm; at 2 MHz it becomes 1540 / 2,000,000 = 0.77 mm, exactly half.

The speed, frequency, and wavelength of a wave are linked by v = f λ. In tissue, the speed of sound is about 1540 m/s and stays essentially constant for ultrasound. If the frequency doubles, the product f λ must stay equal to v. So the new wavelength is λ' = v / (2f) = (1/2)(v / f) = λ/2. In other words, doubling the frequency halves the wavelength. For a quick example, at 1 MHz the wavelength is 1540 / 1,000,000 = 1.54 mm; at 2 MHz it becomes 1540 / 2,000,000 = 0.77 mm, exactly half.

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