If an echo is received after 51.9 μs in tissue with c ≈ 1540 m/s, what is the reflector depth?

Unlock all questions

This demo includes only 20 questions. Upgrade to access hundreds of questions, flashcards, exam simulations, and disable ads.

Full question bankExam simulationsFlashcards
From $24.99Unlock all

Prepare for the Ultrasound Physics Test. Access flashcards and multiple-choice questions, each with hints and explanations. Get set for your exam day!

Multiple Choice

If an echo is received after 51.9 μs in tissue with c ≈ 1540 m/s, what is the reflector depth?

Explanation:
Depth comes from the round-trip travel time of the ultrasound pulse. The reflector’s one-way distance is half the time multiplied by the speed of sound in tissue: depth = (c × t) / 2. Here, t = 51.9 μs = 51.9 × 10^-6 s and c ≈ 1540 m/s. Multiply: 1540 × 51.9e-6 = 0.079926 m. Halving gives 0.039963 m, which is about 3.996 cm. So the reflector is approximately 3.99 cm deep.

Depth comes from the round-trip travel time of the ultrasound pulse. The reflector’s one-way distance is half the time multiplied by the speed of sound in tissue: depth = (c × t) / 2.

Here, t = 51.9 μs = 51.9 × 10^-6 s and c ≈ 1540 m/s. Multiply: 1540 × 51.9e-6 = 0.079926 m. Halving gives 0.039963 m, which is about 3.996 cm. So the reflector is approximately 3.99 cm deep.

More Multiple Choice Questions
Subscribe

Get the latest from Examzify

You can unsubscribe at any time. Read our privacy policy