For a 3.5 MHz transducer in tissue (c ≈ 1540 m/s) with a single-cycle pulse, what is the approximate axial resolution?

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Multiple Choice

For a 3.5 MHz transducer in tissue (c ≈ 1540 m/s) with a single-cycle pulse, what is the approximate axial resolution?

Explanation:
Axial resolution comes from how short the pulse is along the beam. For a single-cycle pulse, the spatial pulse length equals the wavelength, and the axial resolution is roughly half of that SPE length. The wavelength in tissue is λ = c / f. With c ≈ 1540 m/s and f = 3.5 MHz, λ ≈ 1540 / 3.5e6 ≈ 0.000439 m, or about 0.439 mm. Half of that is ~0.219 mm, i.e., about 0.22 mm. So the approximate axial resolution is 0.22 mm.

Axial resolution comes from how short the pulse is along the beam. For a single-cycle pulse, the spatial pulse length equals the wavelength, and the axial resolution is roughly half of that SPE length. The wavelength in tissue is λ = c / f. With c ≈ 1540 m/s and f = 3.5 MHz, λ ≈ 1540 / 3.5e6 ≈ 0.000439 m, or about 0.439 mm. Half of that is ~0.219 mm, i.e., about 0.22 mm. So the approximate axial resolution is 0.22 mm.

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